leetcode260-- Single Number III

# 小郑之家~

### 题目


Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once.

Example:

Input:  [1,2,1,3,2,5]
Output: [3,5]

Note:

The order of the result is not important. So in the above example, [5, 3] is also correct.
Your algorithm should run in linear runtime complexity. Could you implement it using only constant space complexity?




class Solution(object):
def singleNumber(self, nums):
"""
:type nums: List[int]
:rtype: List[int]
"""
xor = 0
for i in nums:
xor ^= i
xor &= -xor # get the last 1 of xor: 10101000 -> 1000
a, b = 0, 0
for i in nums: # devide the numbers into two parts, and a, b should be divided into different part
if i & xor:
a ^= i
else:
b ^= i
return [a, b]